Engineering Homework Help. ME 120 California State University Sacramento Equivalent Equations Exercises
In the piping system shown above, 60 degree F water flows from point 1 to the valve and exits to the atmosphere. Point 1 is 31 feet below the valve outlet. The vertical section of pipe from point 1 to the elbow is 30 feet while the horizontal section of pipe is 50 feet. All pipe has inner diameter 2″ and equivalent roughness of 0.0025 feet. The elbow has loss coefficient KL = 0.5 while for the valve KL = 4.2.
Use the equation (p/γ + v2/2g + z)2 = (p/γ + v2/2g + z)1 + hS – hL or an equivalent equation to find the required pressure at point 1 (in psi gage pressure) for 64 gallon per minute flow from point 1 to the valve outlet (1 ft3 = 7.48 gallons). You can assume the water speed at the valve exit is the same as the speed at point 1.
Your steps should include calculation of the flow Reynolds number, the pipe friction factor and the head losses (or pressure drops) due to pipe and fittings.
